Star pattern programs in C

                                                                                                                  for looping statement go here
Q no 1.Write a C program to print the following pattern:

         *
      *  *
   *  *  *
*  *  *  *

solution

#include<stdio.h>

#include<conio.h>

void main() 

{ 

      char prnt = '*';

      int i, j, nos = 4, s;

      for (i = 1; i <= 5; i++)

      {  

         for (s = nos; s >= 1; s--)

         { // Spacing factor 

              printf(" "); 

         }

         for (j = 1; j <= i; j++)

         { 

               printf("%2c", prnt); 

         } 

         printf("\n"); 

         --nos; // Controls the spacing factor 

       }

       return 0; 

}

Q. No 2 .Write a C program to print the following pattern:

*   *   *   *   *
  *   *   *   *
    *   *   *
      *   *
        *
      *   *
    *   *   *
  *   *   *   *
*   *   *   *   *

Solution :

#include<stdio.h>

#include<conio.h>
int main() 

{
 char prnt = '*';
 int i, j, s, nos = 0;
 for (i = 9; i >= 1; (i = i - 2)) {
  for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
   if ((i % 2) != 0 && (j % 2) != 0) {
    printf("%2c", prnt);
   } else {
    printf("  ");
   }
  }
  printf("\n");
  nos++;
 }
 nos = 3;
 for (i = 3; i <= 9; (i = i + 2)) {
for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {

   if ((i % 2) != 0 && (j % 2) != 0) {
    printf("%2c", prnt);
   } else {
    printf("  ");
   }
  }
  nos--;
  printf("\n");
 }
 return 0;
}

Q. no 3.Write a C program to print the following pattern:

* * * * * * * * * * * * * * * * *
  * * * * * * *   * * * * * * *
    * * * * *       * * * * *
      * * *           * * *
        * * * * * * * * *
          * * * * * * *
            * * * * *
              * * *
                *

Solution :

#include<stdio.h>

#include<conio.h> 
int main() 

{
 char prnt = '*';
 int i, j, k, s, sp, nos = 0, nosp = -1;
 for (i = 9; i >= 3; (i = i - 2)) {
  for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
printf("%2c", prnt);
}
for (sp = nosp; sp >= 1; sp--) {
   printf("  ");
  }
  for (k = 1; k <= i; k++) {
 if (i == 9 && k == 1) {
continue;
}
printf("%2c", prnt);
}
nos++;
nosp = nosp + 2;
printf("\n");
}
nos = 4;
for (i = 9; i >= 1; (i = i - 2)) {
  for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
   printf("%2c", prnt);
  }
  nos++;
  printf("\n");
 }

 return 0;
}

Q no 4.Write a C program to print the following pattern:

          *
        * * *
      * * * * *
    * * * * * * *
  * * * * * * * * *
    * * * * * * *
      * * * * *
        * * *
          *
        * * *
      * * * * *

Solution:

#include<stdio.h>

#include<conio.h>
int main()

 {
 char prnt = '*';
 int i, j, k, s, nos = 4;
 for (i = 1; i <= 5; i++) {
for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
   printf("%2c", prnt);
  }
  for (k = 1; k <= (i - 1); k++) {
if (i == 1) {     continue;
}
printf("%2c", prnt);
}
 printf("\n");   nos--;
}
 nos = 1;
for (i = 4; i >= 1; i--) {
  for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
   printf("%2c", prnt);
  }
  for (k = 1; k <= (i - 1); k++) {
   printf("%2c", prnt);
  }
  nos++;
  printf("\n");
 }
 nos = 3;
 for (i = 2; i <= 5; i++) {
if ((i % 2) != 0) {
for (s = nos; s >= 1; s--) {
    printf("  ");
   }
   for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
   }
  }
  if ((i % 2) != 0) {
   printf("\n");
   nos--;
  }
 }
 return 0;
}

                                    ........to be continued         R.P